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Question

Edge length of FCC unit cell of copper sulphate is:

A
120Ao
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B
170Ao
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C
150Ao
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D
200Ao
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Solution

The correct option is B 150Ao
Zeff=4 for CuSO4
Let the concentration be c

Cu(H2O)2+6+H2O[Cu(H2O)5(OH)]++H3O+
c
cx x x

x2cx=(105)2c105=K=105
c=2×105 mol/litre moles of CuSo4=2×105×12=105 moles
Number of unit cells= 105×NA4=64×1018=1.5×1018

Number of unit cells along one edge of the cube=31.5×1018=1.14×106
Let the edge length of FCC be a
a×1.14×106=17.1mma=150˚A

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