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Aluminium Chloride

Edge length o...

Question

Edge length of the unit cell of NaCl crystal lattice is 552 pm. If ionic radius of Na ion is 95 pm. What is the ionic radius of chloride ion

190 pm

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368 pm

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181 pm

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276 pm

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Solution

The correct option is C 181 pm
$r_{N a}^{+} + r_{c l^{-}} = 276 p m o r 95 + r_{c l^{-}} = 276 p m r_{c l^{-}} = 276 - 95 = 181 p m$

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