$E D T A^{- 4}$ is a X dentate ligand. X is :

mono

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hexa

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tetra

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tertary

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Solution

The correct option is B hexa
$E D T A^{4 -}$ is a hexadentate ligand. (4 oxygen and 2 nitrogen atoms are donor)

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[E D T A]^{4 -}

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