$[E D T A]^{4 -}$ is a

Monodentate ligands

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Bidentate ligands

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Tetradentate ligands

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Hexadentate ligands

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Solution

The correct option is D Hexadentate ligands
It has 6 donor atom

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Similar questions

E D T A^{- 4}

E D T A^{4 -}

N - C o - O

[C o (E D T A)]^{-}

E D T A

EDTA is generally a

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