Question

EF divides the rectangle ABCD in two equal parts.

• A. True
• B. False

Answer 1

The correct option is A

True

$EF$ divides the rectangle, $ABCD$ into two trapeziums.

Area of trapezium $ABFE=\frac{1}{2}\times (AE+BF)\times AB$

$=\frac{1}{2}\times (1+2)\times 4$

$=\frac{1}{2}\times 3\times 4=6c{m}^2$

Area of trapezium $CDEF=\frac{1}{2}\times (FC+ED)\times CD$

$=\frac{1}{2}\times (1+2)\times 4$

$=\frac{1}{2}\times 3\times 4=6c{m}^2$

$\text{Area of both the trapeziums are equal.}$

$\therefore$ $EF$ divides the rectangle $ABCD$ in two equal parts