Question

Effective atomic number of $Ni$ in $Ni(CO{)}_x$ is $36$. Thus, $x=$_________.

Answer 1

Effective atomic number of $Ni$ in $Ni(CO{)}_x$ is $36$. Thus, $x=4$ .
EAN=Effective atomic number
Z=Atomic number of the metal
X = number of electrons lost during the formation of metal ions from its atom.
Y = number of electrons donated by ligands.
The effective atomic number of the complex $\left[Ni{\left(CO\right)}_x\right]$ is $28-0+2x=36$.
Hence, $x=4$