Question

Efficiency of the pulley system.

Answer 1

Applied effort $F_{effort}=50Kgf$

Load $F_{load}=175kgf$

Thus MA of the pulley $MA=\frac{F_{load}}{F_{effort}}$

$\therefore$ $MA=\frac{175}{50}=3.5$

Efficiency of the system $\eta =\frac{MA}{VR}\times 100$

$⟹\eta =\frac{3.5}{4}\times 100=87.5$ %