Eight cuboidal metal boxes with dimensions 60 cm-45 cm-30 cm are to be painted- If the rate of painting is Rs- 200 per m2- find the total cost of painting-

The correct option is A Rs. 234 Total surface area of a cubiod is =2(lb+bh+lh) =2((60 × 45)+(60 × 30)+(45 × 30))=11700 cm^2 1 m=100 cm ...

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Byju's Answer

Standard VIII

Mathematics

Total Surface Area of a Cuboid

Eight cuboida...

Question

Eight cuboidal metal boxes with dimensions $60 c m \times 45 c m \times 30 c m$ are to be painted. If the rate of painting is $R s . 200$ per $m^{2}$ , find the total cost of painting.

R s . 234

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R s . 233

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R s . 134

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R s . 224

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Solution

The correct option is A $R s . 234$
Total surface area of a cubiod is
$= 2 (l b + b h + l h)$
$= 2 ((60 \times 45) + (60 \times 30) + (45 \times 30)) = 11700 c m^{2}$

$1 m = 100 c m$
$11700 c m = 1.17 m^{2}$
$R s .200$ per $m^{2} = 200 \times 1.17 = R s .234$

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Eight cuboidal metal boxes with dimensions 60cm×45cm×30cm are to be painted. If the rate of painting is Rs.200 per m2, find the total cost of painting.

The correct option is A Rs.234Total surface area of a cubiod is=2(lb+bh+lh)=2((60×45)+(60×30)+(45×30))=11700 cm21 m=100 cm11700 cm=1.17 m2Rs.200 per m2=200×1.17=Rs.234

Eight cuboidal metal boxes with dimensions $60 c m \times 45 c m \times 30 c m$ are to be painted. If the rate of painting is $R s . 200$ per $m^{2}$ , find the total cost of painting.

The correct option is A $R s . 234$
Total surface area of a cubiod is
$= 2 (l b + b h + l h)$
$= 2 ((60 \times 45) + (60 \times 30) + (45 \times 30)) = 11700 c m^{2}$

$1 m = 100 c m$
$11700 c m = 1.17 m^{2}$
$R s .200$ per $m^{2} = 200 \times 1.17 = R s .234$