Eight dipoles of charges of magnitude e are placed inside a cube. The total electric flux coming out of the cube will be

\frac{8 e}{ϵ_{0}}

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\frac{16 e}{ϵ_{0}}

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\frac{e}{ϵ_{0}}

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z e r o

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Solution

The correct option is D $z e r o$
$Φ$ = 0 For electric dipole

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Eight dipoles with charges q and -q are placed inside a cube. The total electric flux coming out of the cube will be:

\pm q

\pm

\to E

+ q a n d - q

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