Question

Eight dipoles of charges of magnitude $q$ are placed inside a cube. Then, the total electric flux coming out of the cube will be

• A. $\frac{8q}{ϵ}$
• B. $\frac{16q}{ϵ}$
• C. $\frac{q}{ϵ}$
• D. $0$

Answer 1

The correct option is D $0$

A dipole consist of two charges $q$ and $-q$, where is any charge.

Hence, net charge of a dipole is 0.

Hence, when 8 dipoles are kept inside a cube the net charge $q_{net}$ inside the cube is 0.

And, flux $\varphi =\frac{q_{net}}{{ϵ}_o}$

$⟹\varphi =0$

Answer-(D)