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Surface Energy

Eight droplet...

Question

Eight droplets of mercury, each of radius $1 m m$ , coalesce into a single drop.
(a) Find the radius of the single drop?
[Surface tension of mercury $= 0.465 J / m^{2}$ ].

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Solution

$n =$ number of droplets $= 8$
$r =$ radius of droplets $= 1$ mm
surface tension $T = 0.465 J / m^{2}$
$r = 1$ mm
$= 1 \times 0.001$ m
radius of single drop $= 0.001$ m

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