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Byju's Answer
Standard XII
Chemistry
Relating Translational KE and T
Eight gram ea...
Question
Eight gram each of oxygen and hydrogen at
27
∘
C
will have the total kinetic energy in the ratio of x:y. The value of y is
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Solution
The K.E of a gas at a given temperature is:
K
.
E
=
3
2
n
R
T
now,
n
O
2
=
8
32
n
H
2
=
8
2
K
.
E
(
O
2
)
K
.
E
(
H
2
)
=
(
3
2
)
n
O
2
R
T
(
3
2
)
n
H
2
R
T
=
n
O
2
n
H
2
=
8
32
8
2
=
1
16
hence, y=16
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Relating Translational KE and T
Standard XII Chemistry
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