Eight times the sum of the areas of two circular faces of a cylinder is equal to the four times the curved surface area of the cylinder. It is given that the diameter of the cylinder is 4n, where n is an integer and height of the cylinder is 8 cm. Find the value of n.
Let the radius of the given cylinder be 'r' cm and height be 'h' cm.
Given, height of cylinder = h = 8 cm
Now, area of circular face of cylinder = π r2
Therefore, area of two circular faces = π r2 + πr2 = 2 πr2
Also, curved surface area of cylinder = 2π rh = 2 πr × 8 = 16πr
According to the given condition,
8 × area of two circular faces of cylinder = 4 × curved surface area of cylinder
8 × 2 πr2 = 4 × 16π r
⇒ r2 = 4r
⇒ r = 4
So, r = 4 cm
Hence, diameter of the cylinder = 2 × 4 cm = 8 cm
⇒ 4n = 8
⇒ n = 2