Electric charges -10- C- -5- C- -3- C and -8- C are placed at the corners of a square of side -2m- The potential at the centre of the square is-

The correct option is A 1.8 × 10^5 We know potential = kQr Now potential at centre due to all charges =k(10μ c+5μ c 3μ c+8μ c)1m =(9× 10^9) ...

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Standard XII

Physics

Electric Potential at a Point in Space Due to a Point Charge Q

Electric char...

Question

Electric charges $+ 10 μ C, + 5 μ C, - 3 μ C$ and $+ 8 μ C$ are placed at the corners of a square of side $\sqrt{2} m$ . The potential at the centre of the square is:

1.8 \times 10^{6}

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1.8

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1.8 \times 10^{5}

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18 \times 10^{5}

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Solution

The correct option is A $1.8 \times 10^{5}$

We know potential $= \frac{k Q}{r}$
Now potential at centre due to all charges $= \frac{k (10 μ c + 5 μ c - 3 μ c + 8 μ c)}{1 m}$
$= (9 \times 10^{9}) (20 \times 10^{- 6} c)$
$= 1.8 \times 10^{5} V$

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Electric charges +10μC,+5μC,−3μC and +8μC are placed at the corners of a square of side √2m. The potential at the centre of the square is:

The correct option is A 1.8×105We know potential =kQrNow potential at centre due to all charges =k(10μc+5μc−3μc+8μc)1m=(9×109)(20×10−6c)=1.8×105 V

Electric charges $+ 10 μ C, + 5 μ C, - 3 μ C$ and $+ 8 μ C$ are placed at the corners of a square of side $\sqrt{2} m$ . The potential at the centre of the square is:

The correct option is A $1.8 \times 10^{5}$

We know potential $= \frac{k Q}{r}$
Now potential at centre due to all charges $= \frac{k (10 μ c + 5 μ c - 3 μ c + 8 μ c)}{1 m}$
$= (9 \times 10^{9}) (20 \times 10^{- 6} c)$
$= 1.8 \times 10^{5} V$