Electric current is sent through a resistance of 20 ohm from a battery of EMF 2 volt and of negligible internal resistance . During measurement of current with the help of ammeter ,20% error is incurred .What is the resistance of the ammeter ?
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Solution
Total resistance (without ammeter resistance) = 20 ohm
Battery Voltage = 2V
Theoretically current through the circuit = 2/20 =0 .1A
20% error occurred in the ammeter 0.1×20% = 0.02A
So the reading will be = 0.08 A
So total Resistance including Ammeter =2/0.08 =25