Electric field as a function of distance from the centre of a uniformly charged solid sphere is mathematically :
A
a discontinuos function
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
inversely related to distance from the centre
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
proportional to distance from the centre
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A a discontinuos function
The variation of electric field intensity (E) with distance (r) from the center (O) of the solid sphere is as shown:
i) Electric field intensity at the center of charged solid sphere is zero.
ii) As the distance (r) from the center of solid sphere increases, electric field intensity also increases along (OA) [∵(E∝r)] and becomes maximum at the surface of solid sphere.
iii) As the distance (r) further increases beyond the surface of sphere, electric field intensity varies inversely with r2 and hten decreases.
We see from the graph that there is discontinuity at r=R where electric field intensity is maximum. So, this plot is a discontinuous function.