Question

Electric field at a distance x from origin is given as $E=\frac{100}{x^2}$, then potential difference between points situated at x = 10 m and x = 20 m:

• A. 5 V
• B. 10 V
• C. 15 V
• D. 4 V

Answer 1

The correct option is A 5 V

We have,

$E=\frac{100}{x^2}$

$v=\left|-\int \frac{100}{x^2}dx\right|$

$=\left|-100{\int }_{10}^{20}\frac{dx}{x^2}\right|$

$=100\left(\frac{1}{10}-\frac{1}{20}\right)$

$=\frac{100}{10}\left(\frac{1}{2}\right)$

$=5v$

Hence,

Option $A$ is correct answer.