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Electric Field

Electric fiel...

Question

Electric field at Y is $E_{y}$ and electric field at Z is $E_{z}$ . Find the value of $\frac{E_{z}}{E_{y}}$ .

\frac{\sqrt{3}}{4}

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\frac{\sqrt{4}}{3}

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\frac{4}{3}

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\frac{9}{16}

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\frac{16}{9}

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Solution

The correct option is D $\frac{16}{9}$
The electric at distance r due to charge Q is $E = k Q / r^{2}$
So, $E_{y} = k Q / 4^{2} = k Q / 16$ and $E_{z} = k Q / 3^{2} = k Q / 9$
Thus, $E_{z} / E_{y} = 16 / 9$

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