135
Question
Electric field in space is given as →E=−2x2^i+y^j−2z^k. If potential of point P(3,2,0) is 8 volt, then potential at origin is:
Electric field in space is given as →E=−2x2^i+y^j−2z^k. If potential of point P(3,2,0) is 8 volt, then potential at origin is:
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Solution
The correct option is C −8 V
We know ΔV=−∫→E.→dr=−∫(Exdx+Eydy+Ezdz)
V0−Vp=−{∫03−2x2dx+∫02ydy+∫00−2zdz}
V0−8=−{23(x3)30+(y22)02+0}=−{18−2}=−16
V0=−8 V
We know ΔV=−∫→E.→dr=−∫(Exdx+Eydy+Ezdz)
V0−Vp=−{∫03−2x2dx+∫02ydy+∫00−2zdz}
V0−8=−{23(x3)30+(y22)02+0}=−{18−2}=−16
V0=−8 V
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