Question

Electric field inside the capacitor when distance is $2.5cm$:

• A. $15\times {10}^{2}V/m$
• B. $3\times {10}^{3}V/m$
• C. $12\times {10}^{3}V/m$
• D. $6\times {10}^{3}V/m$

Answer 1

The correct option is C $12\times {10}^{3}V/m$

The electric field inside the capacitor is

$E=\frac{V}{d}$

By substituting the above values we get

$E=\frac{300V}{2cm}$

The electric field should be $15\times {10}^{3}V/m$

As the distance is increased so the electric field will decrease as it is inversely proportional to the distance between the plates.

$E=\frac{300}{2.5\times {10}^2}$

Hence the electric field is $12\times {10}^{3}V/m$