Question

Electric field intensity due to an electric dipole falls off at large distance,at a much faster rate than electric field due to a single charge explain

Answer 1

Electric filed due to single charge is fall of for a large distance as $\frac{1}{r^2}$and for a dipole it is proportional to $\frac{1}{r^3}$.
And in case of dipole field not only depend upon distance r but also angle between the position vector r dipole moment p.