Inside the spherical charge for a radius or a distance lesser than that of the radius of a sphere, there will be no charge enclosed. Then, as per Gauss's law, if the charge is not getting enclosed after constructing a Gaussian sphere, then the electric field intensity is zero. Remember there will be an electric field perpendicular to the surface of the shell. And it is calculated using Gauss's law. So the final answer is, E = 0 for r < R i.e. inside a spherical shell, as it is hollow.