Electric field of a dipole is related to distance $r$ as

E \propto \frac{1}{r^{3}}

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E \propto \frac{1}{r}

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E \propto \frac{1}{r^{2}}

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E \propto \frac{1}{r^{4}}

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Solution

The correct option is A $E \propto \frac{1}{r^{3}}$
$E_{d i p o l e} = \frac{1}{4 π ε_{0}} . \frac{p}{r^{3}}$
$\Rightarrow E \propto \frac{1}{r^{3}}$

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Similar questions

ρ = ρ_{0} e^{- α r^{3}}

ρ_{0}

α

\frac{ρ_{0}}{x ε_{0} α r^{2}} (1 - e^{- α r^{3}})

x

r > R_{2}

E = \frac{1}{X π ε_{0}} \frac{Q}{r^{2}}

Electric intensity due to an electric dipole varies with distance r as $E α r^{n}$ , where ‘n’ is

R_{1} < r < R_{2}

E = \frac{Q}{X π ε_{0} r^{2}} [\frac{r^{3} - R_{1}^{3}}{R_{2}^{3} - R_{1}^{3}}]

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