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Standard XII

Physics

Ohm's Law in Scalar Form

Electric flux...

Question

Electric flux through a surface of area $10 m^{2}$ lying in the $x y$ plane is (if $\to E =^i + \sqrt{2}^j + \sqrt{3}^k N / C$ )

141.4

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200

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100

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17.32

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Solution

The correct option is D $17.32$
We know that electric flux
$ϕ = \int \to E . \to d s = \to E . \to S$
Since the surface is lying in the $x - y$ plane, its area vector will be along the $z -$ axis.
$\to S = 10 m^{2}^k$
$E =^i + \sqrt{2}^j + \sqrt{3}^k N / C^{- 1}$ [Given]
$⟹ ϕ = (^i + \sqrt{2}^j + \sqrt{3}^k) . (10^k)$
$⟹ ϕ = 10 \sqrt{3} N C^{- 1} m^{2} = 17.32 N C^{- 1} m^{2}$

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Similar questions

Q. Electric flux through a surface of area

100 m^{2}

lying in the xy plane is (in Vm) if

\to E =^i + \sqrt{2}^j + \sqrt{3}^k

Q. If

\to E =^i + \sqrt{2}^j + \sqrt{3}^k

, then find the Electric flux through surface of area

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Q. If the electric flux through a surface of area

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\to E =^i + \sqrt{2}^j + \sqrt{3}^k

Q. The electric field in a region is given by

\to E = (1200^i + 1600^j) N/C

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Q. The electric field in a region is given by

\to E = (\frac{3}{5} E_{o}^i + \frac{4}{5} E_{o}^j) N/C

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and

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Ohm's Law in Scalar Form

Standard XII Physics

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Electric flux through a surface of area 10 m2 lying in the xy plane is (if →E=^i+√2 ^j+√3 ^k N/C)

The correct option is D 17.32We know that electric flux ϕ=∫→E.→ds=→E.→S Since the surface is lying in the x−y plane, its area vector will be along the z− axis. →S=10 m2 ^k E=^i+√2 ^j+√3 ^k N/C−1[Given] ⟹ϕ=(^i+√2 ^j+√3 ^k).(10 ^k) ⟹ϕ=10√3 NC−1m2=17.32 NC−1m2

Electric flux through a surface of area $10 m^{2}$ lying in the $x y$ plane is (if $\to E =^i + \sqrt{2}^j + \sqrt{3}^k N / C$ )