Question

Electric flux through a surface of area $100m^2$ lying in the xy plane is (in Vm) if $\overrightarrow{E}=\hat{i}+\sqrt{2}\hat{j}+\sqrt{3}\hat{k}$

• A. $100$
• B. $141.4$
• C. $173.2$
• D. $200$

Answer 1

The correct option is C $173.2$

Electric flux, $\varphi =\int \overrightarrow{E}.\hat{n}ds$

given, $\hat{n}=\hat{k},ds=100m^2\overrightarrow{E}=\hat{i}+\sqrt{2}\hat{j}+\sqrt{3}\hat{k}$

$\varphi =(\hat{i}+\sqrt{2}\hat{j}+\sqrt{3}\hat{k}).\hat{k}100=100\sqrt{3}=173.2$