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Question

Electric potential at any point is $$V = -5x+3y+\sqrt{15}z$$, then the magnitude of the electric field is :


A
32
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B
42
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C
52
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D
7
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Solution

The correct option is C $$7$$
Electric potential at point is $$V=-5x+3y+\sqrt{15}z$$
Electric field is $$\vec{E}=-\nabla V=-(\hat{i}\frac{\partial }{\partial x}+\hat{j}\frac{\partial }{\partial y}+\hat{k}\frac{\partial }{\partial z})(-5x+3y+\sqrt{15}z)=-(-5\hat{i}+3\hat{j}+\sqrt{15}\hat{k})$$
$$|\vec{E}|$$=7

Physics
NCERT
Standard XII

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