Question

# Electric potential at any point is $$V = -5x+3y+\sqrt{15}z$$, then the magnitude of the electric field is :

A
32
B
42
C
52
D
7

Solution

## The correct option is C $$7$$Electric potential at point is $$V=-5x+3y+\sqrt{15}z$$Electric field is $$\vec{E}=-\nabla V=-(\hat{i}\frac{\partial }{\partial x}+\hat{j}\frac{\partial }{\partial y}+\hat{k}\frac{\partial }{\partial z})(-5x+3y+\sqrt{15}z)=-(-5\hat{i}+3\hat{j}+\sqrt{15}\hat{k})$$$$|\vec{E}|$$=7PhysicsNCERTStandard XII

Suggest Corrections

0

Similar questions
View More

Same exercise questions
View More

People also searched for
View More