Question

Electricity passed through a solution of alcl3 ,13.5gm al is deposited no.of Faraday must be

Answer 1

the reaction at cathode is

Al ( 3+) + 3e---------->Al. (n=3)

→applying the equation

w = E×i×t/F

by substituting the values

♦ i × t =
13.5 /(27/3)×F

=13.5/9 ×F

=1.5 F

I hope this helps :)