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Oxyacids of Phosphorus

Electrochemic...

Question

Electrochemical equivalent of $C u$ in the reaction
$C u^{+ 2} + 2 e^{-} \to C u$ is:

\frac{63.5}{96.5}

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\frac{63.5}{96500 \times 2}

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\frac{63.5 \times 2}{96500}

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\frac{96500}{63.5 \times 2}

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Solution

The correct option is B $\frac{63.5}{96500 \times 2}$
Electrochemical equivalence $= \frac{E q u i v a l e n t m a s s}{F} = Z$

Equivalent mass of $C u = \frac{M o l a r m a s s}{v a l e n c y} = \frac{M}{2} = \frac{63.5}{2}$

Value of $F = 96500$

$Z = \frac{63.5}{2 \times 96500}$

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