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Byju's Answer
Standard XII
Chemistry
Nernst Equation
Electrode pot...
Question
Electrode potential for Mg electrode varies according to the equation
E
M
g
2
+
|
M
g
=
E
M
g
2
+
|
M
g
Θ
-
0.059
2
l
o
g
1
[
M
g
2
+
]
. The graph of
E
M
g
2
+
|
M
g
Vs
l
o
g
[
M
g
2
+
]
is
Open in App
Solution
E
M
g
2
+
|
M
g
=
0.059
2
l
o
g
[
M
2
+
]
+
E
o
M
g
2
+
|
M
g
Graph of
E
M
g
2
+
|
M
g
V/S
l
o
g
[
M
2
+
]
is as follows.
Where slope
=
0.059
2
Suggest Corrections
1
Similar questions
Q.
Electrode potential for Mg electrode varies according to the equation.
E
M
g
2
+
M
g
=
E
∘
M
g
2
+
M
g
−
0.059
2
l
o
g
(
1
M
g
2
+
)
The graph of
E
M
g
2
+
M
g
v
s
l
o
g
[
M
g
2
+
]
is
Q.
Calculate the emf of the cell.
M
g
(
s
)
|
M
g
2
+
(
0.2
M
)
∥
A
g
+
(
1
×
10
−
3
)
|
A
g
E
∘
A
g
+
|
A
g
=
+
0.8
v
o
l
t
,
E
∘
M
g
2
+
|
M
g
=
−
2.37
v
o
l
t
What will be the effect on emf if concentration of
M
g
2
+
ion is decreased to
0.1
M
Q.
The e.m.f of the cell is:
M
g
|
M
g
2
+
(
1
M
)
|
|
P
b
2
+
(
1
M
)
|
P
b
[
E
0
(
P
b
/
P
b
2
+
)
=
0.14
V
,
E
0
(
M
g
2
+
/
M
g
)
=
−
2.37
V
]
Q.
How would you determine the standard electrode potential of the
M
g
2
+
|
M
g
?
Q.
Calculate the
Δ
G
o
and equilibrium constant of the reaction at
27
∘
C
M
g
+
C
u
+
2
⇌
M
g
+
2
+
C
u
E
M
g
2
+
/
M
g
=
−
2.37
V
;
E
C
u
2
+
/
C
u
=
0.34
V
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