Electrode potential of hydrogen electrode is18mV then concentration of H+ is
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Solution
electrode potential can be calculated by the equation Ecell= E0 cell- (0.059/n) log [H2 ]/[H+] Here E0cell= 0v n=1 since the number of electrons involved in the reaction is one Given Ecell = 18 mv Also [H2 ]=1 since it is not an ion Therefore equation becomes 18 mv= - 0.059 log 1/[H+]= - 0.018 v/.059= -.305 1/[H+] = antilog (-.305) = 0.4955 [H+]= 1/ 0.4955 = 2.02 M