Electrode potential of hydrogen electrode is18mV then concentration of H+ is

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Solution

electrode potential can be calculated by the equation Ecell= E0 cell- (0.059/n) log [H₂]/[H+]
Here E0cell= 0v
n=1 since the number of electrons involved in the reaction is one
Given Ecell = 18 mv
Also [H₂]=1 since it is not an ion
Therefore equation becomes
18 mv= - 0.059
log 1/[H+]= - 0.018 v/.059= -.305
1/[H+] = antilog (-.305) = 0.4955
[H+]= 1/ 0.4955 = 2.02 M

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