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Extraction of Highly Reactive Metals

Electrolysis ...

Question

Electrolysis involves oxidation and reduction respectively at:

A

Anode, Cathode

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B

Cathode, Anode

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C

Anode, Anode

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D

Cathode, Cathode

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Solution

The correct option is A
Anode, Cathode

In the electrolysis process, anions move towards the cathode and cations moves towards the anode. Oxidation occurs at the anode and reduction occurs at the cathode.

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Q. Assertion: Starting from aq. copper [II] sulphate solution, equations for the reactions at the cathode and anode during electrolysis of aq.

C u S O_{4}

using active copper electrodes is;
at anode:

C u^{+ 2} + 2 e^{-} \to C u

C u \to C u^{+ 2} + 2 e^{-}

Reason: Oxidation always take place at anode and reduction at cathode.

Q. Consider the following relations for emf of an electrochemical cell:

(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii)) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode) (i v)) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

Q. Consider the following relations for emf of an electrochemical cell :

(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode)
(ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode)
(iii) EMF of cell = (Reduction potential of anode) + (Reduction potential of cathode)
(iv) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

Which of the above relation(s) is correct?

Q. Electrolysis of dil.

H_{2} {SO}_{4}

liberates gases at anode and cathode respectively

Q. Assertion :Anode is the electrode at which oxidation occurs and cathode is the electrode at which reduction occurs. Reason: Anode and cathode in electrochemical cells and electrolytic cells have opposite polarity.

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