MyQuestionIcon

29

You visited us 29 times! Enjoying our articles? Unlock Full Access!

Extraction of Highly Reactive Metals

Electrolysis ...

Question

Electrolysis involves oxidation and reduction respectively at:

A

Anode, Cathode

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

Cathode, Anode

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

Anode, Anode

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

Cathode, Cathode

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
Anode, Cathode

In the electrolysis process, anions move towards the cathode and cations moves towards the anode. Oxidation occurs at the anode and reduction occurs at the cathode.

Suggest Corrections

thumbs-up

0

Similar questions

Q. Assertion: Starting from aq. copper [II] sulphate solution, equations for the reactions at the cathode and anode during electrolysis of aq.

C u S O_{4}

using active copper electrodes is;
at anode:

C u^{+ 2} + 2 e^{-} \to C u

C u \to C u^{+ 2} + 2 e^{-}

Reason: Oxidation always take place at anode and reduction at cathode.

Q. Consider the following relations for emf of an electrochemical cell:

(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii)) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode) (i v)) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

Q. Consider the following relations for emf of an electrochemical cell :

(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode)
(ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode)
(iii) EMF of cell = (Reduction potential of anode) + (Reduction potential of cathode)
(iv) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

Which of the above relation(s) is correct?

Q. Electrolysis of dil.

H_{2} {SO}_{4}

liberates gases at anode and cathode respectively

Q. Assertion :Anode is the electrode at which oxidation occurs and cathode is the electrode at which reduction occurs. Reason: Anode and cathode in electrochemical cells and electrolytic cells have opposite polarity.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Extraction of Highly Reactive Metals

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Extraction of Highly Reactive Metals

Standard X Chemistry

Join BYJU'S Learning Program

CrossIcon