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Introduction to Alkanes

Electrolysis ...

Question

Electrolysis of H2SO4 (conc.) gives the following atanode (1) H2 (2) O2 (3) H2S203 (4) H2S2O8

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Q. During an electrolysis of conc.

H_{2} S O_{4}

, perdisulphuric acid

(H_{2} S_{2} O_{8})

O_{2}

form in equimolar amount. The amount of

H_{2}

that will form simultaneously will be:

(2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{+} + 2 e^{-})

Q. During the electrolysis of conc

H_{2} S O_{4}

, it was found that

H_{2} S_{2} O_{8}

O_{2}

were liberated in a molar ratio of 3:1. How many moles of

H_{2}

were found is terms of moles of

H_{2} S_{2} O_{8}

?
[Express your answer as :

3 \times

H_{2}

; integer answer is between 0 and 15].

Q. Marshall's acid or perdisulphuric acid

(H_{2} S_{2} O_{8})

can be prepared by electrolytic oxidation of

H_{2} S O_{4}

2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{\oplus} + 2 e^{-}

O_{2}

H_{2}

are byproducts. In such an electrolysis 9.72 L of

H_{2}

O_{2}

were produced at S.T.P. What is the weight of

H_{2} S_{2} O_{8}

Q. Peroxydisulfuric acid

(H_{2} S_{2} O_{8})

can be prepared by electrolytic oxidation of

H_{2} S O_{4}

2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{+} + 2 e

O_{2}

H_{2}

are by products. In such on electrolysis

0.87

H_{2}

3.36

O_{2}

were generated at STP. Report the mass of

H_{2} S_{2} O_{8}

formed in decagram (write nearest integer).

Marshalls acid is prepared by the electrolytic oxidation of $H_{2} S O_{4}$ as $2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{\oplus} + 2 e^{-}$

Oxygen and hydrogen are byproducts. In such Electrolysis 2.24 L of $H_{2}$ amd 0.56 L $O_{2}$ were produced at STP. The weight of $H_{2} S_{2} O_{8}$ formed is:

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