Electrolysis of molten NaCl gives ________.

N a

and

H_{2}

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N a

and

O_{2}

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H_{2}

and

O_{2}

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N a

and

C l_{2}

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Solution

The correct option is D $N a$ and $C l_{2}$
In electrolysis of molten NaCl sodium ions migrate to the cathode.
${N a}^{+} + e^{-} \to N a$
Chloride ions migrate the other way, towards the anode.
${C l}^{-} \to \frac{1}{2} {C l}_{2} + e^{-}$
The overall reaction is the breakdown of sodium chloride into its elements is:
$2 N a C l \to N a (s) + {C l}_{2} (g)$

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Similar questions

Given are the reactions occuring during the electrolysis of sodium chloride solution:

$2 C l^{-} \to C l_{2} + 2 e^{-}$
$2 H_{2} O + 2 e^{-} \to H_{2} + 2 O H^{-}$

Which of the following is correct regarding liberation of electrolytic products?

F^{-}, O^{2 -}, N a^{+}, M g^{2 +}

H_{2}

C l_{2}

C l_{2}

H_{2} O

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