Electrolysis of water is a decomposition reaction. The mole ratio of hydrogen and oxygen gases liberated during electrolysis of water is :

1:1

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2:1

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4:1

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1:2

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Solution

The correct option is B 2:1
$2 H_{2} O \to 2 H_{2} + O_{2}$

The mole ratio of hydrogen and oxygen gases liberated during the electrolysis of water is $2 : 1$ .

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What is the ratio of hydrogen and oxygen, liberated by weight, in the electrolysis of water?

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