Electrolysis of X gives Y at the anode. Vacuum distillation of Y gives $H_{2} O_{2}$ . The number of peroxy (O-O) bonds present in X and Y respectively are

1, 1

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1, 2

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0, 1

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0, 0

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Solution

The correct option is C $0, 1$
Hydrogen peroxide is manufactured by electrolysis of 50 % sulphuric acid followed by vacuum distillation. The distillate is 30 % hydrogen [peroxide. The first product of electrolysis is peroxy disulphuric acid which is obtained by the electrolytic oxidation of sulphuric acid.
$2 H_{2} S O_{4} \to 2 H^{+} + 2 H S O_{4}^{-}$
$2 H S O 4^{-} \to H_{2} S_{2} O_{8} + 2 e^{-}$ ( at anode)
Peroxy- disulphuric acid $H_{2} S_{2} O_{8}$ reacts with water during distillation to form hydrogen peroxide.
$H_{2} S_{2} O_{8} (a q) + 2 H_{2} O (l) \to 2 H_{2} S O_{4} (a q) + H_{2} O_{2} (a q)$
$2 H^{+} + 2 e^{-} \to H_{2} (g)$ (at cathode)
Hence X is $H_{2} S O_{4}$ and Y is $H_{2} S_{2} O_{8}$ . Therefore the number of peroxy bonds present in X and Y are zero and 1 respectively.

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Q. A metal carbonate X on treatment with a mineral acid liberates a gas which when passed through aqueous solution of a substance Y gives back X. The substance Y on reaction with the gas obtained at anode during electrolysis of brine gives a compound Z which can decolorise coloured fabrics. The compounds X, Y and Z respectively are.

Two acids have been derived from

H_{2} O_{2}

by replacing

H

(S O_{2} O H)

group. Both the acids have one peroxy linkage

H - O - O - H

H - O - O - S O_{2} H_{2} S O_{5} - O H

H - O - O - H

H O - S O_{2} - O - O - H_{2} S_{2} O_{8} S O_{2} - O H

Based on the above study, answer the following question:

H_{2} S_{2} O_{8}

is obtained at anode by the electrolysis of ____________

A metal carbonate X on treatment with a mineral acid liberates a gas which when passed through aqueous solution of a substance Y gives back X. The substance Y on reaction with the gas obtained at anode during electrolysis of brine gives a compound Z which can decolorise coloured fabrics. The compounds X, Y and Z respectively are

Question 45.
A metal carbonate X on reacts with acid and gives a gas which when passed through a solution Y gives the carbonate back. On the other hand, a gas G that is obtained at the anode during electrolysis of brine is passed on dry Y, it gives a compound Z, used for disinfecting drinking water. Identify X, Y, G and Z.

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Electrolysis of X gives Y at the anode. Vacuum distillation of Y gives H2O2. The number of peroxy (O-O) bonds present in X and Y respectively are

Electrolysis of X gives Y at the anode. Vacuum distillation of Y gives $H_{2} O_{2}$ . The number of peroxy (O-O) bonds present in X and Y respectively are