Question

# Electromagnetic radiation falls on a metallic body whose work function is $$2eV$$. For particular radiation of frequency $$\nu$$, the maximum kinetic energy of the photoelectron is found to be $$4eV$$. Find the maximum kinetic energy (in eV) of photoelectron for the radiation of $$\dfrac {5\nu}{3}.$$

A
8
B
6
C
16
D
12

Solution

## The correct option is A $$8$$Electromagnetic radiation falls on a metallic body whose work function is 2eV.$$h\nu=\phi + KE_{max}\Rightarrow h\nu=2+4$$$$\Rightarrow h\nu=6eV$$Again, $$h(\dfrac {5\nu}{3})=2+KE_{max}$$$$\dfrac {5}{3}\times 6=2+KE_{max}$$$$KE_{max}=8eV$$So, the answer is option (A).PhysicsNCERTStandard XII

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