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Question

Electromagnetic radiation falls on a metallic body whose work function is $$2eV$$. For particular radiation of frequency $$\nu$$, the maximum kinetic energy of the photoelectron is found to be $$4eV$$. Find the maximum kinetic energy (in eV) of photoelectron for the radiation of $$\dfrac {5\nu}{3}.$$


A
8
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B
6
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C
16
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D
12
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Solution

The correct option is A $$8$$
Electromagnetic radiation falls on a metallic body whose work function is 2eV.
$$h\nu=\phi + KE_{max}\Rightarrow h\nu=2+4$$
$$\Rightarrow h\nu=6eV$$

Again, $$h(\dfrac {5\nu}{3})=2+KE_{max}$$

$$\dfrac {5}{3}\times 6=2+KE_{max}$$

$$KE_{max}=8eV$$
So, the answer is option (A).

Physics
NCERT
Standard XII

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