Electromagnetic radiations of wavelength 242 nm is just sufficient to ionize Sodium atom. Then the ionization energy of Sodium in kJ mole⁻¹ is

494.65

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Solution

The correct option is A
494.65
I.E. of one sodium atom = hC/λ
& I.E. of one mole Na atom hC/λ NA
= 6.62 × 1034 × 3 × 108 × 6.02 × 10²³/(242 × 10⁻⁹ )= 494.65kj.mol

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Similar questions

Q. An electromagnetic radiation of wavelength 242 nm is just sufficient to ionize a sodium atom. The ionization energy of sodium in

k J m o l^{- 1}

is .

An electromagnetic radiation of wavelength 242 nm is just sufficient to ionize a sodium atom. Calculate the ionization energy of sodium in kJ ${m o l}^{- 1}$ .

Q. An electromagnetic radiation of wavelength 242 nm is just sufficient to ionize a sodium atom. The ionization energy of sodium in

k J m o l^{- 1}

is .

Q. Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. What is the ionization energy of sodium per atom?

An electromagnetic radiation of wavelength 242 nm is just sufficient to ionize a sodium atom. Calculate the ionization energy of sodium in kJ ${m o l}^{- 1}$ .

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Electromagnetic radiations of wavelength 242 nm is just sufficient to ionize Sodium atom. Then the ionization energy of Sodium in kJ mole−1 is

The correct option is A494.65I.E. of one sodium atom = hC/λ& I.E. of one mole Na atom hC/λ NA= 6.62 × 1034 × 3 × 108 × 6.02 × 1023/(242 × 10−9 )= 494.65kj.mol

Electromagnetic radiations of wavelength 242 nm is just sufficient to ionize Sodium atom. Then the ionization energy of Sodium in kJ mole⁻¹ is

The correct option is A
494.65
I.E. of one sodium atom = hC/λ
& I.E. of one mole Na atom hC/λ NA
= 6.62 × 1034 × 3 × 108 × 6.02 × 10²³/(242 × 10⁻⁹ )= 494.65kj.mol