MyQuestionIcon

5

You visited us 5 times! Enjoying our articles? Unlock Full Access!

Fringe Width in YDSE

Electromagnet...

Question

Electromagnetic waves of wavelength $500 n m$ are incident on a YDSE apparatus. Both slits of the apparatus are of the same width. Given $d = 3 m m$ , $D = 2 m$ . Intensity at the central maxima is $1 W / m^{2}$ . The intensity in $(W / m^{2})$ at a point $1 m m$ above maxima of 1st order is

Open in App

Solution

We know that,
$β = \frac{λ D}{d} = \frac{1}{3} m m$ that means it can have 3 maximas in $1 m m$ . At a point $1 m m$ above the 1st order maxima = 4th order maxima will be formed. Hence Intensity will be $1 W / m^{2}$ .

Suggest Corrections

thumbs-up

0

Similar questions

Q. The distance between two slits in a

Y D S E

3 m m

. The distance of the screen from the slits is

1 m

. Microwaves of wavelength

1 m m

are incident on the plane of the slits normally. Find the distance of the first maxima on the screen from the central maxima. Also find the total number of maxima on the screen.

In given YDSE experiment a plane wavefront of

λ = 600 n m

is incident on slits at angle

θ = 30^{\circ}

as shown in figure. Slit separation is

d = 0.5 m m

Q. In a YDSE apparatus, separation between the slits d = 1mm,

λ = 600 n m

and D = 1m. Assume that each slit produce same intensity on the screen. The minimum distance between two points on the screen having

75 %

intensity of the maximum intensity is

n \times 10^{- 4} m

Q. Light from a source emitting two wavelengths

λ_{1}

λ_{2}

is allowed to fall on Young's double-slit apparatus after filtering one of the wavelengths. The position of interference maxima is noted. When the filter is removed both the wavelengths are incident and it is found that maximum intensity is produced where the the fourth maxima occurred previously. If other wavelength is filtered, at the same location the third maxima is found. What is the ratio of wavelengths?

Q. In YDSE of equal width slits, if intensity at the centre of screen is

I_{0}

, then intensity at a distance of

β / 4

from the central maxima is (

β

is the fringe width) :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Fringe Width

PHYSICS

Watch in App

explore_more_icon

Explore more

Fringe Width in YDSE

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon