Electron precise hydride among the following is:

C H_{4}

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N H_{3}

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B_{2} H_{6}

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H_{2} O

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Solution

The correct option is A $C H_{4}$
$B_{2} H_{6}$ is electron deficient hydride.
$H_{2} O$ and $N H_{3}$ are electron rich hydrides since we have more number of electrons compared to the number of electrons required to form all the covalent bonds.
$C H_{4}$ is electrons precise hydride since, there are exact number of electrons to form normal covalent bonds for completing octet.

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Similar questions

Which of the following hydride is 'electron-precise' type?

Question 4

Which of the following hydrides is elctron-precise hydride?

(a) $B_{2} H_{6}$ (b) $N H_{3}$ (c) $H_{2} O$ (d) $C H_{4}$

H_{2}

H_{2} O

L i A l H_{4}

B F_{3}

B_{2} H_{6}

P H_{3}

C H_{4}

H F

C H_{4}

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