Electron-transfer reactions can be separated into two half reactions.
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Solution

The correct option is A 1
Electron-transfer reactions can be separated into two half reactions, oxidation half reaction and reduction half reaction.
For example, consider the reaction between mercuric chloride and stannous chloride.
$2 H g C l_{2} + S n C l_{2} \to H g_{2} C l_{2} + S n C l_{4}$
In this reaction, $S n C l_{2}$ is oxidized into $S n C l_{4}$ and $H g C l_{2}$ is reduced into $H g_{2} C l_{2}$ .
The net ionic equation for the redox reaction can be written as
$2 H g^{2 +} + S n^{2 +} \to H g_{2}^{2 +} + S n^{4 -}$
The net ionic equation for the oxidation half reaction can be written as
$S n^{2 +} \to S n^{+ 4} + 2 e^{-}$
The net ionic equation for the reduction half reaction can be written as
$2 H g^{2 +} + 2 e^{-} \to H g_{2}^{2 +}$

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