Question

Electronegativity values of some elements are given.
[H = 2.20, C = 2.55 , K = 0.82, Mg = 1.31, O = 3.44, Cl = 3.16]
Identify the nature of chemical bond present in the following compounds on the basis of their electronegativity values.
a) $H_{2}O$
b) KCl
c) ${\mathrm{MgCl}}_2$
d) ${\mathrm{CH}}_4$
​​​​​​​e) ${\mathrm{CCl}}_4$

Answer 1

Compound	Difference in Electronegativity values	Type of Bonding
$H_{2}O$	3.44 – 2.2 = 1.24	Covalent bond
KCl	3.16 – 0.82 = 2.34	Ionic bond
${\mathrm{MgCl}}_2$	3.16 – 1.31 = 1.85	Ionic bond
${\mathrm{CH}}_4$	2.55 – 2.20 = 0.35	Covalent bond
${\mathrm{CCl}}_4$	3.16 - 2.55 = 0.61	Covalent bond