Electronic configuration In case of 4s and 3d which would be written first?

Open in App

Solution

Electrons are filled in increasing order of orbital energy. The arrow shows that the order in which the orbitals should be filled.
Looking at the figure one can easily deduce that 4s will be filled before 3d {that's because 4s has lesser energy than 3d}.

Suggest Corrections

Similar questions

Q. Which rule explains the electronic configuration of chromium is [Ar]

3 d^{5} 4 s^{1}

instead of [Ar]

3 d^{4} 4 s^{2}

My sir told that while writing subshell configuration we 1st write 3d and then 4s. But the electrons fill first in 4s and then in 3d My doubt is that which will come first 4s or 3d??why??

Q. Which one of the following (a or b) electronic configuration is more stable and why?
(a)

3 d^{4} 4 s^{2}

(b)

3 d^{5} 4 s^{1}

Q. Why chromium has electronic configuration

3 d^{5} 4 s^{1}

and not

3 d^{4} 4 s^{2}

?
Transition metals form complex compounds :

Q. Configuration of

B r^{-}

is :

[A r] 3 d^{10} 4 s^{2} 4 p^{6}

The electronic configuration of

B r^{+ 2}

would be identical with the element:

Join BYJU'S Learning Program

Electronic configuration In case of 4s and 3d which would be written first?

Electrons are filled in increasing order of orbital energy. The arrow shows that the order in which the orbitals should be filled. Looking at the figure one can easily deduce that 4s will be filled before 3d {that's because 4s has lesser energy than 3d}.

Electrons are filled in increasing order of orbital energy. The arrow shows that the order in which the orbitals should be filled.
Looking at the figure one can easily deduce that 4s will be filled before 3d {that's because 4s has lesser energy than 3d}.