Electronic configuration of $F e^{3 +}$ ion is

[A r] 3 d^{6}

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[A r] 4 s^{2} 3 d^{6}

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[A r] 3 d^{5}

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[A r] 4 s^{2} 3 d^{3}

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Solution

The correct option is C $[A r] 3 d^{5}$
Iron is a transition element (d-block). Its atomic number is 26 i.e. 26 electrons.
Its electronic configuration is,
$F e - 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{6}$ or
$[A r] 4 s^{2} 3 d^{6}$ .
$F e^{3 +}$ is formed by loosing two electron from 4s and one electron from 3d.
So, the electronic configuration of $F e^{3 +}$ will be $[A r] 3 d^{5}$ .

Hence, option (c) is the correct answer.

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Similar questions

Question 14

The pair of ions having same electronic configuration is.............

(a) $C r^{3 +}, F e^{3 +}$ (b) $F e^{3 +}, M n^{2 +} +$ (c) $F e^{3 +}, C o^{3 +}$ (d) $S C^{3 +}, C r^{3 +}$

[A r] 3 d^{6}

(A t o m i c N u m b e r : M n = 25, F e = 26, C o = 27, N i = 28)

[M (H_{2} O)_{6}]^{2 +}

(F e)

F e S O_{4}

F e_{2} (S O_{4})_{3}

(F e^{3 +})

F e^{3 +}

[A r] 3 d^{5}

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