Electronic configuration of $F e^{3 +}$ ion is given corrrectly by

1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{6}, 4 s^{2}

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1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}

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1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}, 4 s^{1}

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1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{8}

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Solution

The correct option is B $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}$
$1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{6}, 4 s^{2}$ is the correct electronic configuration of Fe atom. When iron turns into Ferric ion $F e^{3 +}$ , it looses three electrons and becomes positive ion therefore the 3+ sign.
Electrons are lost from the outermost orbit first i.e from $4 s^{2}$ , 2 electrons are lost and then from $3 d^{6}$ , 1 electron is lost therefore the configuration for ion $F e^{3 +}$ becomes $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}$

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Similar questions

Which of the following is the stable electronic configuration of $F e^{3 +}$ ion?

Question 14

The pair of ions having same electronic configuration is.............

(a) $C r^{3 +}, F e^{3 +}$ (b) $F e^{3 +}, M n^{2 +} +$ (c) $F e^{3 +}, C o^{3 +}$ (d) $S C^{3 +}, C r^{3 +}$

(F e)

F e S O_{4}

F e_{2} (S O_{4})_{3}

(F e^{3 +})

F e^{3 +}

[A r] 3 d^{6}

(A t o m i c N u m b e r : M n = 25, F e = 26, C o = 27, N i = 28)

[M (H_{2} O)_{6}]^{2 +}

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