Electronic configuration of most electronegative element is:

1 s^{2} . 2 s^{2} . 2 p^{4} . 3 s^{1}

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1 s^{2} . 2 s^{2} . 2 p^{6} . 3 s^{2} . 3 p^{5}

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1 s^{2} . 2 s^{2} . 2 p^{5}

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1 s^{2} . 2 s^{2} . 2 p^{6} . 3 s^{1} . 3 p^{8}

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Solution

The correct option is C $1 s^{2} . 2 s^{2} . 2 p^{5}$
Most electronegative element is Fluorine. its atomic number is 9. Its electronic configuration is 1s $^{2}$ 2s $^{2}$ 2p $^{5}$

Hence, the correct option is $C$

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Similar questions

Question 21

The electronic configuration of the outer most shell of the most electronegative elements is

(a) $2 s^{2} 2 p^{5}$

(b) $3 s^{2} 3 p^{5}$

(d) $5 s^{2} 5 p^{5}$

1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}

1 s^{2}, 2 s^{2}, 2 p^{5}

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