Electronic configuration of some elements is given in colum I and their electron gain enethalpies are given in Column II mathc the electronic configuration with electron gain enthalpy
$\begin{matrix} C o l u m n I (E l e c t r o n i c c o n f i g u r a t i o n) & C o l u m n I I E l e c t r o n g a i n e n t h a l p y / K J m o l^{- 1} A . 1 s^{2} 2 s^{2} 2 p^{6} & - 53 B . 1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{1} & - 328 C . 1 s^{2}, 2 s^{2}, 2 p^{5} & - 141 D . 1 s^{2}, 2 s^{2}, 2 p^{4} & + 48 \end{matrix}$

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Solution

A. this electronic configuration corresponds to the noble gas i.e. neon Since, Noble gases have $+ △_{e g} H$ values, therefore, electronic configuration (A) corresponds to the $△_{e g} H = + 48 K J m o l^{- 1}$
B. This electronic configuration corresponds to the alkali metal i.e. potassium. Alkall metals have small negative $△_{e} g H$ value hence, electronic configuration (B) corresponds to $△_{e g} H = - 53 K J m o l^{- 1}$
C. This elecgronic configurations corresponds to the hetogen i.e., flucring since, halogens haven high negative $△_{e g} H$ values therefore electronic configuration (C) corresponds to \ $△_{e g} H = - 328 K J m o l^{- 1}$
D. This electronic configuration corresponds to the chalcogen i.e.e, oxygen. Since chalcogens have \triangle_{eg} H values negative than those fo haogens, thererfore electronic configuration (D) correspond to $△_{e g} H = - 141 K J m o l^{- 1}$

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