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Aufbau Principle

Electronic tr...

Question

Electronic transitions in H atom takes place from n₂ to n₁ shell such that:
$n_{2} + 2 n_{1} = 11$ and $2 n_{2} - 3 n_{1} = 8$
What is the total number of photons which are in Balmer series in the given transitions?

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Solution

The correct option is D 5
Solving $n_{2} + 2 n_{1} = 11$ and $2 n_{2} - 3 n_{1} = 8$
$n_{1} = 2$ and $n_{2} = 7$
The number of lines in the Balmer series $= 7 - 2 = 5$

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