wiz-icon
MyQuestionIcon
MyQuestionIcon
20
You visited us 20 times! Enjoying our articles? Unlock Full Access!
Question

Electrons having a velocity v of 2×106ms1 pass undeviated through a uniform electric field E of intensity 5×104Vm1 and a uniform magnetic field B.
(i) Find the magnitude of magnetic flux density B of the magnetic field.
(ii) What is the direction of B, if v is towards right and E is vertically downwards in the plane of this paper?

Open in App
Solution

(i) Given: v=2×106m/s
E=5×104V/m
We know that v=E/B
B=5×1042×106=0.025T
=2.5×102T.

(ii) Direction of magnetic field intensity is vertically inside into the plane of paper.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorization of Polynomials
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon