Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-rays tube. The cutoff wavelength (λ0) of the emitted X-rays is
Using de-Broglie equation, λ=hp where p=√2mE
⟹ λ=h√2mE
Energy of the X-ray emitted, E=hcλo
∴ λ=h√2m×hcλo
⟹λo=2mcλ2h